Reaction $H_2S_2O_{8(aq)} \xrightarrow{H_2O} 2H_2SO_4 + x.$ What is product $x$?

Electrolysis of $X$ gives $Y$ at anode. Vacuum distillation of $Y$ gives $H_2O_2$. The number of peroxy $(O-O)$ bonds present in $X$ and $Y$ respectively are :

On shaking $H_2O_2$ with acidified potassium dichromate and ether,the ethereal layer becomes:

Consider the following reaction:
$2 HSO_{4}^{-}(aq)$ $\xrightarrow[\text{(2) Hydrolysis}]{\text{(1) Electrolysis}} H_{2}S_{2}O_{8}(aq)$ $\xrightarrow{\text{Hydrolysis}} 2 HSO_{4}^{-}(aq) + 2 H^{+}(aq) + A(aq)$
The dihedral angle in product $A$ in its solid phase at $110 \ K$ is ....$^{\circ}$

Which of the following is incorrect regarding $H_2O_2$?

The equation $H_2S + H_2O_2 \to S + 2H_2O$ represents: